x^2+33x+242=0

Solution for x^2+33x+242=0 equation:

x^2+33x+242=0

a = 1; b = 33; c = +242;
Δ = b2-4ac
Δ = 332-4·1·242
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-11}{2*1}=\frac{-44}{2}
=-22
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+11}{2*1}=\frac{-22}{2}
=-11
$